The correct order of stabilities of the following superoxides is

K O_{2} > R b O_{2} > C s O_{2}

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$R b O_{2} > C s O_{2} > K O_{2}$

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C s O_{2} > R b O_{2} > K O_{2}

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$K O_{2} > C s O_{2} > R b O_{2}$

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Solution

The correct option is C $C s O_{2} > R b O_{2} > K O_{2}$
As we go down the group, the size of the cation increases. In general, the stability is high when both the ions are of a similar size. $O_{2}^{-}$ is a large anion and thus it can be stabilized by a large cation, as similar size of ions leads to higher coordination number and thus higher lattice energy. Hence, the stability is in the order $C s O_{2} > R b O_{2} > K O_{2}$

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