The correct order of stability for the following species is-B 2- B 2-and B 2-A- B 2- B 2- B 2-B- B 2- B 2- B 2-C- B 2- B 2- B 2-D- B 2- B 2- B 2-

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Standard XII

Chemistry

Bond Length

The correct o...

Question

The correct order of stability for the following species is:
$B_{2}, B_{2}^{-} a n d B_{2}^{+}$

B_{2} < B_{2}^{+} < B_{2}^{-}

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B_{2}^{+} < B_{2} < B_{2}^{-}

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B_{2} < B_{2}^{-} < B_{2}^{+}

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B_{2}^{-} < B_{2} < B_{2}^{+}

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Solution

The correct option is B $B_{2}^{+} < B_{2} < B_{2}^{-}$
From molecular orbital theory, $B_{2}^{-}$ has bond order = 1.5, $B_{2}$ has bond order= 1 and $B_{2}^{+}$ has bond order= 0.5. So, option (b) is correct

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Similar questions

Which of the following is correct?
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c) $(a - b)^{2} = a^{2} - b^{2}$
d) $(a + b)^{2} = a^{2} + 2 a b - b^{2}$

What is the point of contact between the hyperbola
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Q. If θ =

\frac{a}{b}

, then

\frac{(a sinθ - b cosθ)}{(a \sin θ + b cosθ)}

= ?
(a)

\frac{(a^{2} + b^{2})}{(a^{2} - b^{2})}

(b)

\frac{(a^{2} - b^{2})}{(a^{2} + b^{2})}

(c)

\frac{a^{2}}{(a^{2} + b^{2})}

(d)

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Q. Prove the following :

∣ ∣ ∣ ∣ ∣ \begin{matrix} b^{2} + c^{2} & a b & a c a b & c^{2} + a^{2} & b c c a & c b & a^{2} + b^{2} \end{matrix} ∣ ∣ ∣ ∣ ∣

= ∣ ∣ ∣ ∣ ∣ \begin{matrix} b^{2} + c^{2} & a^{2} & a^{2} b^{2} & c^{2} + a^{2} & b^{2} c^{2} & c^{2} & a^{2} + b^{2} \end{matrix} ∣ ∣ ∣ ∣ ∣ = 4 a^{2} b^{2} c^{2}

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The correct order of stability for the following species is: B2, B−2 and B+2

The correct option is B B+2<B2<B−2From molecular orbital theory, B−2 has bond order = 1.5, B2 has bond order= 1 and B+2 has bond order= 0.5. So, option (b) is correct

The correct order of stability for the following species is:
$B_{2}, B_{2}^{-} a n d B_{2}^{+}$

The correct option is B $B_{2}^{+} < B_{2} < B_{2}^{-}$
From molecular orbital theory, $B_{2}^{-}$ has bond order = 1.5, $B_{2}$ has bond order= 1 and $B_{2}^{+}$ has bond order= 0.5. So, option (b) is correct