The correct order of stability for the following super oxides is :

K O_{2} > R b O_{2} > C s O_{2}

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R b O_{2} > C s O_{2} > K O_{2}

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C s O_{2} > R b O_{2} > K O_{2}

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K O_{2} > C s O_{2} > R b O_{2}

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Solution

The correct option is B $C s O_{2} > R b O_{2} > K O_{2}$
A small ction can stabilize a small anion and a large cation can stabilize a large anion. Stability of superoxides increses down the group in alkali metals.

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Similar questions

Q. Assertion :The oxidation state of superoxide ion in

{K O}_{2}, {C s O}_{2}

and

{R b O}_{2}

- \frac{1}{2}

. Reason: Since the oxidation state of an alkali metal in any compound is always

+ 1

, the oxidation state of oxygen is

\frac{1}{2}

in the

O_{2}^{-}

ion.

Read the above assertion and reason and choose the correct option regarding it.

Q. The oxidation state of Na, K, Rb respectively in

N a_{2} O_{2}, K O_{2}, R b O_{2}

is :

The stability of $K_{2} O$ , $K_{2} O_{2}$ and $K O_{2}$ is in order $K_{2} O < K_{2} O_{2} < K O_{2}$ . The increasing stability at the size of metal ion increases is due to stabilization of:

$R b O_{2}$ is

Q. Out of

K O_{2}, N O_{2}, N O

and

K_{2} O_{2}

unpaired electron are present in:

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The correct order of stability for the following super oxides is :

The correct option is B CsO2>RbO2>KO2A small ction can stabilize a small anion and a large cation can stabilize a large anion. Stability of superoxides increses down the group in alkali metals.

The correct option is B $C s O_{2} > R b O_{2} > K O_{2}$
A small ction can stabilize a small anion and a large cation can stabilize a large anion. Stability of superoxides increses down the group in alkali metals.