The correct order of stability is

N_{2} > N_{2}^{+} > N_{2}^{-}

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N_{2} > N_{2}^{-} > N_{2}^{+}

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N_{2}^{+} > N_{2}^{-} > N_{2}

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None of these

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Solution

The correct option is A $N_{2} > N_{2}^{+} > N_{2}^{-}$
Bond order for $N_{2} = 3$
Bond order for $N_{2}^{+} = 2.5$
Bond order for $N_{2}^{-} = 2$
Bond order $\propto$ Stability of molecule.
Therefore, the correct order of stability is:
$N_{2} > N_{2}^{+} > N_{2}^{-}$

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