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Standard XII

Chemistry

Liquefaction of Gases and Critical Constants

The correct o...

Question

The correct order of temperature for a real gas is:
I. Boyle's temperature
II. Critical temperature
III. Inversion temperature

III > I > II

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I > II > III

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II > I > III

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I > III > II

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Solution

The correct option is A III > I > II
As we know,
Inversion temperature
$T_{i} = \frac{2 a}{R b}$
Critical temperature
$T_{c} = \frac{8 a}{27 R b}$
Boyle temp.
$T_{B} = \frac{a}{R b}$
So order is:
III > I > II

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The correct order of temperature for a real gas is:I. Boyle's temperatureII. Critical temperatureIII. Inversion temperature

The correct option is A III > I > IIAs we know,Inversion temperature Ti=2aRbCritical temperatureTc=8a27RbBoyle temp.TB=aRbSo order is:III > I > II

The correct order of temperature for a real gas is:
I. Boyle's temperature
II. Critical temperature
III. Inversion temperature

The correct option is A III > I > II
As we know,
Inversion temperature
$T_{i} = \frac{2 a}{R b}$
Critical temperature
$T_{c} = \frac{8 a}{27 R b}$
Boyle temp.
$T_{B} = \frac{a}{R b}$
So order is:
III > I > II