The correct order of third ionization energies of Na, Mg, and AI is?

Mg>Na>Al

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Na > Mg >Al

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Na > Al > Mg

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Al > Na > Mg

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Solution

The correct option is B Mg>Na>Al
I.P of $N a, M g, A l$
$N a^{2 +} = 1 s^{2} 2 s^{2} 2 p^{5}$
$M g^{+} = [N e]_{10} 3 s^{0}$
$A l^{2 +} = [N e]_{10} 3 s^{1}$
So,according to this electron configuration,it would be very difficult to remove one more electron from $M g$ as it has completed octet,
Applying same logic to others,
we get order, $M g > N a > A l$

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Similar questions

The first ionistation enthalpies of Na, Mg, Al, and Si are in the order
(a) Na< Mg > Al < Si (b) Na> Mg > Al > Si
(c) Na< Mg< Al< Si (d) Na> Mg> Al < Si

Q. If

I_{M g} = First ionization energy of Mg

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Choose the correct option:

Question 17
Arrange the following elements in the order of their decreasing metallic character
Na, Si, Cl, Mg, Al

(a) Cl > Si >Al > Mg >Na
(b) Na >Mg >Al >Si > Cl
(c) Na > Al > Mg > Cl > Si
(d) Al > Na> Si > Ca> Mg

$N a^{+} . M g^{2 +}, A l^{3 +}$ and $S i^{4 +}$ are isoelectronic. The order of their ionic size is

Q. Arrange the following in the order given below : Increasing order of ionization potential of

N a, A l, M g, S i

is :

N a < A l < M g < S i

. if true enter 1 ,else enter 0.

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The correct order of third ionization energies of Na, Mg, and AI is?

The correct option is B Mg>Na>AlI.P of Na,Mg,AlNa2+=1s22s22p5Mg+=[Ne]103s0Al2+=[Ne]103s1So,according to this electron configuration,it would be very difficult to remove one more electron from Mg as it has completed octet,Applying same logic to others,we get order,Mg>Na>Al