The correct order of unpaired electrons present in d orbitals for elements $F e, T i, C r$ and $C o$ is :

C r = F e > C o > T i

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F e > C o > C r > T i

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C r > F e > C o > T i

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C r = F e > T i > C o

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Solution

The correct option is A $C r > F e > C o > T i$
$C r = [A r] 4 s^{1} 3 d^{5};$ 6 unpaired electrons

$F e = [A r] 4 s^{2} 3 d^{6};$ 4 unpaired electrons

$C o = [A r] 4 s^{2} 3 d^{7};$ 3 unpaired electrons

$T i = [A r] 4 s^{2} 3 d^{2};$ 2 unpaired electrons

$C r > F e > C o > T i$

Hence, option $C$ is correct.

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Similar questions

For the four successive transition elements (Cr, Mn, Fe and Co), what is the order of stability of their +2 states?

(At. Nos. Cr = 24, Mn = 25, Fe = 26, Co = 27)

E^{0} M^{2 +} / M

V^{2 +} < C r^{2 +} < M n^{2} < F e^{2 +}

N i^{2 +} < C o^{2 +} < F e^{2 +} < M n^{2 +}

C o^{3 +} < F e^{3 +} < C r^{3 +} < S c^{3 +}

S c < T i < C r < M n

C o^{+ 3}, N i^{+ 2}, C r^{+ 3}, F e^{+ 2}, F e^{+ 3}, C u^{+ 2}, T i^{+ 2}, C o^{+ 2}

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