Question

The correct order regarding electronegativity of hybrid orbitals of carbon is :

• A. $sp<s{p}^2<s{p}^3$
• B. $sp<s{p}^2>s{p}^3$
• C. $sp>s{p}^2<s{p}^3$
• D. $sp>s{p}^2>s{p}^3$

Answer 1

The correct option is D $sp>s{p}^2>s{p}^3$

Electronegativity increases as s-character in hybrid orbital increases.