The correct orders of reactivity towards $S_{N} 1$ reactions is ?

I > I I > I I I

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I I > I I I > I

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I I I > I I > I

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I > I I I > I I

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Solution

The correct option is B $I I > I I I > I$

(Refer to Image)
The order towards $S N_{1}$ reaction is
$I I > I I I > I$
The carbocation formed at Bridge-head carbon is unstable. So, $I$ is less reactive, $I I$ is more reactive because it forms $3^{o}$ - carbocation which is highly stable.

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