The correct polarizibility order is:

I^{-} > B r^{-} > C l^{-} > F^{-}

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I^{-} > B r^{-} > F^{-} > C l^{-}

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I^{-} < B r^{-} < C l^{-} < F^{-}

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I^{-} < B r^{-} < F^{-} < C l^{-}

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Solution

The correct option is A $I^{-} > B r^{-} > C l^{-} > F^{-}$
As size of anion increases, its polarizability increases.

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Similar questions

Q. The correct order of polarizability is

I^{-}, B r^{-}, C l^{-}, F^{-}

Q. The correct order of polarizability is

I^{-}, B r^{-}, C l^{-}, F^{-}

Among halogens, the correct order of amount of energy released in electron gain (electron gain enthalpy ) is
(a) F > Cl > Br > I (b) F < Cl < Br < I (c) F < Cl > Br > I (d) F < Cl < Br < I

Q. Arrange the following bonds according to their average bond energies in descending order:

C - C l, C - B r, C - F, C - I

Q. Which of the following options does not give to the correct trends indicated against it?
(I)

F_{2} > C l_{2} > B r_{2} > I_{2}

: Bond dissociation energy
(II)

F_{2} > C l_{2} > B r_{2} > I_{2}

: Oxidizing nature
(III)

C l > F > B r > I

: Electron gain enthalpy
(IV)

F > C l > B r > I

: Electronegativity

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The correct polarizibility order is:

The correct option is A I−>Br−>Cl−>F−As size of anion increases, its polarizability increases.

The correct option is A $I^{-} > B r^{-} > C l^{-} > F^{-}$
As size of anion increases, its polarizability increases.