You visited us 1 times! Enjoying our articles? Unlock Full Access!

Polarity and Dipole Moments

The correct r...

Question

The correct reactivity order of alcohols towards $H - X$ will be:
(I) $C H_{2} = C H - O H$
(II) $C H_{2} = C H - C H_{2} O H$
(III) $C H_{3} - C H_{2} - O H$
(IV) $C H_{3} - C H | O H - C H_{3}$

I I > I > I I I > I V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

I V > I I I > I I > I

No worries! We‘ve got your back. Try BYJU‘S free classes today!

I I > I V > I > I I I

No worries! We‘ve got your back. Try BYJU‘S free classes today!

I I > I V > I I I > I

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is B $I I > I V > I I I > I$
Due to the stability of carbocation because of resonance and hyperconjugation,
order is
$C H_{2} = C H - \oplus C H_{2} > C H_{3} - \oplus C H - C H_{3} > C H_{3} - \oplus C H_{2} > C H_{2} = \oplus C H$

Suggest Corrections

Similar questions

C H_{3} - C H C l - C H_{2} - C H_{3}

;

C H_{3} - C H = C H - C H_{3}

I

I I

C H_{3} - C = ¨ N - O H

;

C H_{3} - C H = ¨ N - O H

I I I

I V

The number of stereogenic centres in these structures are, respectively:

Arrange the following alcohols in order of increasing ease of dehydration
$C H_{3} C H_{2} O H$ $C_{6} H_{5} C H_{2} O H$
I II

$C l_{3} C C H_{2} O H$ $F_{3} C C H_{2} O H$
III IV

Q. Correct order at C-H bond dissociation energy of following compound:-
(I)

C H_{3} - H

(II)

C H_{3} - C H_{2} - H

(III)

C H_{3} = C H - C H_{2} - H

(IV)

C_{6} H_{5} - H

Which of the following compounds gives fastest reaction with HBr and why

(i) (CH3)3 COH

(ii) CH3 CH2 CH2OH

(iii) CH3 CHOH CH3

(iv) CH3 (CH3) CH CH2OH

Q. Decreasing order of stability of following alkenes is..
(i)

{C H}_{3} - C H = {C H}_{2}

(ii)

{C H}_{3} - C H = C H - {C H}_{3}

(iii)

{C H}_{3} - C_{3} = C H - {C H}_{3}

(iv)

{C H}_{3} - {C H}_{3} | C = {C H}_{3} | C - {C H}_{3}

Join BYJU'S Learning Program

The correct reactivity order of alcohols towards H−X will be:(I) CH2=CH−OH(II) CH2=CH−CH2OH(III) CH3−CH2−OH(IV) CH3−CH|OH−CH3

The correct option is B II>IV>III>IDue to the stability of carbocation because of resonance and hyperconjugation,order is CH2=CH−⊕CH2>CH3−⊕CH−CH3>CH3−⊕CH2>CH2=⊕CH

The correct reactivity order of alcohols towards $H - X$ will be:
(I) $C H_{2} = C H - O H$
(II) $C H_{2} = C H - C H_{2} O H$
(III) $C H_{3} - C H_{2} - O H$
(IV) $C H_{3} - C H | O H - C H_{3}$

The correct option is B $I I > I V > I I I > I$
Due to the stability of carbocation because of resonance and hyperconjugation,
order is
$C H_{2} = C H - \oplus C H_{2} > C H_{3} - \oplus C H - C H_{3} > C H_{3} - \oplus C H_{2} > C H_{2} = \oplus C H$