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Standard VII

Physics

Electric Current and Electric Cell

The correct r...

Question

The correct relation between $B$ and $M$ for a small current-carrying coil is :

B = \frac{μ_{0} M}{2 x^{3}}

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B = \frac{μ_{0} M}{x^{3}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B = \frac{μ_{0} M}{π x^{3}}

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B = \frac{μ_{0} M}{2 π x^{3}}

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Solution

The correct option is D $B = \frac{μ_{0} M}{2 π x^{3}}$
The relationship between the Magnetic Flux Density $(B)$ and Magnetisation Feild $(M)$ is
$B = \frac{μ_{0} m}{2 π x^{3}}$
Hence the correct answer is $B = \frac{μ_{0} m}{2 π x^{3}}$

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The correct relation between B and M for a small current-carrying coil is :

The correct option is D B=μ0M2πx3The relationship between the Magnetic Flux Density (B) and Magnetisation Feild (M) is B=μ0m2πx3Hence the correct answer is B=μ0m2πx3

The correct relation between $B$ and $M$ for a small current-carrying coil is :

The correct option is D $B = \frac{μ_{0} M}{2 π x^{3}}$
The relationship between the Magnetic Flux Density $(B)$ and Magnetisation Feild $(M)$ is
$B = \frac{μ_{0} m}{2 π x^{3}}$
Hence the correct answer is $B = \frac{μ_{0} m}{2 π x^{3}}$