The correct relationship between critical temperature ( $T_{c}$ ) and Boyle's temperature ( $T_{g}$ ) for $C O_{2}$ gas is:

T_{B} > T_{c}

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T_{B} < T_{c}

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T_{B} = T_{c}

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nothing can be predicted

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Solution

The correct option is A $T_{B} > T_{c}$
As we know that $T_{b} : T_{c} = 28 : 8$
So, $T_{B} > T_{C}$
Options (A) is correct.

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Which of the following statements on critical constants of gases are correct?

I : Larger the $\frac{T_{c}}{P_{c}}$ value of a gas, larger would be the excluded volume.

II : Critical temperature ( $T_{c}$ ) of a gas is greater than its Boyle's temperature ( $T_{B}$ ).

III : At the critical point in the Van der Walls gas isotherm.

$⟮ \frac{d P}{d V_{m}} ⟯ T_{c} = 0$

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