The correct relationship betwen the mechanical advantage (M.A.), the velocity ratio (V. R.) and the efficiency $η$ is :

(a) $M . A = η \times V . R .$ (b) $V . R = η \times M . A$

(c) $η = M . A \times V . R$ (d) none of these.

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Solution

$η = \frac{L \times d_{L}}{E \times d_{E}} = \frac{L}{E} \times \frac{1}{\frac{d_{E}}{d_{L}}} = \frac{M . A .}{V . R .}$

$M . A = η \times V . R .$

So, the correct choice is (a).

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Relation Between MA and VR

Standard X Physics

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The correct relationship betwen the mechanical advantage (M.A.), the velocity ratio (V. R.) and the efficiency η is : (a) M.A=η×V.R. (b) V.R=η×M.A (c)η=M.A×V.R (d) none of these.

η=L×dLE×dE=LE×1dEdL=M.A.V.R. M.A=η×V.R. So, the correct choice is (a).

The correct relationship betwen the mechanical advantage (M.A.), the velocity ratio (V. R.) and the efficiency $η$ is :

(a) $M . A = η \times V . R .$ (b) $V . R = η \times M . A$

(c) $η = M . A \times V . R$ (d) none of these.

$η = \frac{L \times d_{L}}{E \times d_{E}} = \frac{L}{E} \times \frac{1}{\frac{d_{E}}{d_{L}}} = \frac{M . A .}{V . R .}$

$M . A = η \times V . R .$

So, the correct choice is (a).