Question

The correct relationship betwen the mechanical advantage (M.A.), the velocity ratio (V. R.) and the efficiency $\eta$ is :

(a) $M.A=\eta \times V.R.$ (b) $V.R=\eta \times M.A$

(c)$\eta =M.A\times V.R$ (d) none of these.

Answer 1

$\eta =\frac{L\times d_L}{E\times d_E}=\frac{L}{E}\times \frac{1}{\frac{d_E}{d_L}}=\frac{M.A.}{V.R.}$

$M.A=\eta \times V.R.$

So, the correct choice is (a).