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Gay Lussac's Law

The correct r...

Question

The correct representation of Graham's law of diffusion is:

A

\frac{r_{1}}{r_{2}} = \frac{v_{1} / t_{1}}{v_{2} / t_{2}}

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B

\frac{r_{1}}{r_{2}} = \sqrt{\frac{d_{2}}{d_{1}}}

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C

\frac{r_{1}}{r_{2}} = \sqrt{\frac{M_{2}}{M_{1}}}

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D

\frac{r_{1}}{r_{2}} = \frac{P_{2}}{P_{1}} \sqrt{\frac{M_{2}}{M_{1}}}

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Solution

The correct option is C $\frac{r_{1}}{r_{2}} = \sqrt{\frac{M_{2}}{M_{1}}}$
Graham's law shows that the rate of effusion of a gas is inversely proportional to the square root of the mass.

Rate $\propto \sqrt{\frac{1}{mass}}$

$\frac{R a t e 1}{R a t e 2} = \sqrt{\frac{M a s s (2)}{M a s s (1)}}$

$\Rightarrow \frac{R_{1}}{R_{2}} = \sqrt{\frac{M_{2}}{M_{1}}}$

Hence, the correct option is $C$

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