Question

The correct sequence of arrangements of the following compounds in order of decreasing oxidation number of iodine is:

• A. $ICl$, $HI{O}_4$, $I_2$, $HI$
• B. $HI{O}_4$, $HI$, $I_2$, $I_2{O}_5$
• C. $HI{O}_4$, $I_2{O}_5$, $I_2$, $HI$
• D. $HI$, $I_2$, $HI{O}_4$, $I_2{O}_5$

Answer 1

The correct option is C $HI{O}_4$, $I_2{O}_5$, $I_2$, $HI$

$\stackrel{+7}{HI{O}_4},\stackrel{+5}{I_2{O}_5},\stackrel{0}{I_2},\stackrel{-1}{HI}$
+7 > + 5 > 0 > -1 oxidation number order.