The correct sequence of bond enthalpy of $^{'} C — X^{'}$ bond is :

C H_{3} - C l > C H_{3} - F > C H_{3} - B r > C H_{3} - l

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C H_{3} - F < C H_{3} - C l < C H_{3} - B r < C H_{3} - l

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C H_{3} - F > C H_{3} - C l > C H_{3} - B r > C H_{3} - l

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C H_{3} - F < C H_{3} - C l > C H_{3} - B r > C H_{3} - l

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Solution

The correct option is C $C H_{3} - F > C H_{3} - C l > C H_{3} - B r > C H_{3} - l$
The size of halogen atom increases from $F t o I$ hence bond length from $C - F t o C - I$ increases due to decrease of effective nuclear charges on electrons.
$∴$ Bond enthalpy from $C H_{3} - F t o C H_{3} - I$ decreases.
$∙$ So Correct Answer is option (c)

$C - X$ Bond Bond dissociation enthalpies/ $k J m o l^{- 1}$

$C H_{3} - F$

$C H_{3} - C l$

$C H_{3} - B r$

$C H_{3} - l$ 452

351

293

234

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$C - X$ Bond	Bond dissociation enthalpies/ $k J m o l^{- 1}$
$C H_{3} - F$ $C H_{3} - C l$ $C H_{3} - B r$ $C H_{3} - l$	452 351 293 234