The correct sequence of bond enthalpy of $C - X$ bond is

C H_{3} - F < C H_{3} - C l < C H_{3} - B r < C H_{3} - I

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C H_{3} - F > C H_{3} - C l > C H_{3} - B r > C H_{3} - I

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C H_{3} - F < C H_{3} - C l > C H_{3} - B r > C H_{3} - I

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C H_{3} - C l > C H_{3} - F > C H_{3} - B r > C H_{3} - I

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Solution

The correct option is B $C H_{3} - F > C H_{3} - C l > C H_{3} - B r > C H_{3} - I$
Bond enthalpy is inversely proportional to the bond length.
Larger the bond length, smaller is the energy required to break the bond. The bond length order of $C - X$ bond in methyl halides depends on the size of the halogen atom.
The size of halogen atom increases from $F t o I$ hence bond length increase from $C - F t o C - I$ .
Thus, the correct order of bond enthalpy is
$C H_{3} - F > C H_{3} - C l > C H_{3} - B r > C H_{3} - I$

Hence, option (B) is the correct answer.

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