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Question

The correct sequence of decrease in the bond angles of the following hydrides is


A
NH3> PH3> AsH3> SbH3
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B
NH3> AsH3> PH3> SbH3
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C
SbH3> AsH3> PH3> NH3
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D
PH3> NH3> AsH3> SbH3
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Solution

The correct option is A NH3> PH3> AsH3> SbH3
NH3 has sp3 hybridisation with bond angle 1070 where as PH3, AsH3, SbH3 has pure orbitals overlapping with bond angle around 900

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