You visited us 22 times! Enjoying our articles? Unlock Full Access!

Coordinated Covalent Bond

The correct s...

Question

The correct sequence of decrease in the bond angles of the following hydrides is

NH₃> PH₃> AsH₃> SbH₃

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

NH₃> AsH₃> PH₃> SbH₃

No worries! We‘ve got your back. Try BYJU‘S free classes today!

SbH₃> AsH₃> PH₃> NH₃

No worries! We‘ve got your back. Try BYJU‘S free classes today!

PH₃> NH₃> AsH₃> SbH₃

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
NH₃> PH₃> AsH₃> SbH₃

$N H_{3}$ has $s p^{3}$ hybridisation with bond angle $107^{0}$ where as $P H_{3}, A s H_{3}, S b H_{3}$ has pure orbitals overlapping with bond angle around $90^{0}$

Suggest Corrections

Similar questions

1. S b H_{3} > N H_{3} > A s H_{3} > P H_{3}

2. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

3. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

4. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

1. S b H_{3} > N H_{3} > A s H_{3} > P H_{3}

2. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

3. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

4. N H_{3} > P H_{3} > A s H_{3} > S b H_{3}

N H_{3}, P H_{3}, A s H_{3}, S b H_{3}

S i F_{4} < S i C l_{4} < S i B r_{4} < S i I_{4}

N H_{3} > S b H_{3} > A s H_{3} > P H_{3}

N H_{3} > S b H_{3} > A s H_{3} > P H_{3}

N H_{3} > S b H_{3} > A s H_{3} > P H_{3}

Out of NH₃, PH₃, AsH₃ and SbH₃ the most basic hydride is:

Join BYJU'S Learning Program