The correct sequence of decreasing number of π-bonds in the structures of H2SO3,H2SO4andH2S2O7 is:
A
H2SO3>H2SO4>H2S2O7
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
H2SO3>H2S2O7>H2SO3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
H2S2O7>H2SO4>H2SO3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
H2S2O7>H2SO3>H2SO4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is CH2S2O7>H2SO4>H2SO3
The correct sequence of decreasing number of π-bonds is: H2S2O7(4)>H2SO4(2)>H2SO3(1)
The number inside the brackets indicates the number of π-bonds.