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Byju's Answer
Standard XII
Chemistry
Sulphur Trioxide
The correct s...
Question
The correct sequence of decreasing number of
π
-bonds in the structures of
H
2
S
O
3
,
H
2
S
O
4
a
n
d
H
2
S
2
O
7
is:
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Solution
The correct sequence of decreasing number of
π
-bonds is:
H
2
S
2
O
7
(
4
)
>
H
2
S
O
4
(
2
)
>
H
2
S
O
3
(
1
)
The number inside the brackets indicates the number of
π
-bonds.
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Similar questions
Q.
Identify the correct sequence of increasing number of
π
-bonds in the structures of the following molecules.
(I)
H
2
S
2
O
6
(II)
H
2
S
O
3
(III)
H
2
S
2
O
5
Q.
Consider the following sulphur based oxoacids.
H
2
S
O
3
,
H
2
S
O
4
,
H
2
S
2
O
8
and
H
2
S
2
O
7
. Amongst these oxoacids, the number of those with peroxo
(
O
−
O
)
bond is ______.
Q.
The total number of diprotic acids among the following is:
H
3
P
O
4
,
H
2
S
O
4
,
H
3
P
O
3
,
H
2
C
O
3
,
H
2
S
2
O
7
,
H
3
B
O
3
,
H
3
P
O
2
,
H
2
C
r
O
4
,
H
2
S
O
3
Q.
Find the total number of diprotic acids among the following
H
3
P
O
4
,
H
2
S
O
4
,
H
3
P
O
3
,
H
2
C
O
3
,
H
2
S
2
O
7
,
H
3
B
O
3
,
H
3
P
O
2
,
H
2
C
r
O
4
,
H
2
S
O
3
Q.
What would be the sum of the number of
π
− bonds in the following molecules:
I
.
H
2
S
2
O
6
I
I
.
H
2
S
O
3
I
I
I
.
H
2
S
2
O
5
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