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Question

The correct sequence of decreasing number of pi-bonds in the structures of H2SO3,H2SO4 and H2S2O7 is:

A
H2SO3>H2SO4>H2S2O7
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B
H2S2O7>H2SO3>H2SO4
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C
H2SO4>H2S2O7>H2SO3
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D
H2S2O7>H2SO4>H2SO3
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Solution

The correct option is D H2S2O7>H2SO4>H2SO3
The correct sequence of decreasing number of pi-bonds is H2S2O7(4)>H2SO4(2)>H2SO3(1). The numbers in bracket indicate the number of pi bonds.
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