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Oxyacids Of Sulphur

The correct s...

Question

The correct sequence of decreasing number of pi-bonds in the structures of $H_{2} S O_{3}, H_{2} S O_{4}$ and $H_{2} S_{2} O_{7}$ is:

A

H_{2} S O_{3} > H_{2} S O_{4} > H_{2} S_{2} O_{7}

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B

H_{2} S_{2} O_{7} > H_{2} S O_{3} > H_{2} S O_{4}

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C

H_{2} S O_{4} > H_{2} S_{2} O_{7} > H_{2} S O_{3}

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D

H_{2} S_{2} O_{7} > H_{2} S O_{4} > H_{2} S O_{3}

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Solution

The correct option is D $H_{2} S_{2} O_{7} > H_{2} S O_{4} > H_{2} S O_{3}$
The correct sequence of decreasing number of pi-bonds is $H_{2} S_{2} O_{7} (4) > H_{2} S O_{4} (2) > H_{2} S O_{3} (1)$ . The numbers in bracket indicate the number of pi bonds.

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