The correct sequence of decreasing order of reactivity of hydrolysis of acid chlorides is :

P h C O C l > p - O_{2} N C_{6} H_{4} C O C l > p - C H_{3} O C_{6} H_{4} C O C l

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P h C O C l > p - C H_{3} O C_{6} H_{4} C O C l > p - O_{2} N C_{6} H_{4} C O C l

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p - O_{2} N C_{6} H_{4} C O C l > P h C O C l > p - C H_{3} O C_{6} H_{4} C O C l

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p - O_{2} N C_{6} H_{4} C O C l > p - C H_{3} O C_{6} H_{4} C O C l > P h C O C l

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Solution

The correct option is C $p - O_{2} N C_{6} H_{4} C O C l > P h C O C l > p - C H_{3} O C_{6} H_{4} C O C l$
The hydrolysis of acid chloride involves a nucleophilic attack on the fairly positive carbon atom by one of the lone pairs on the oxygen of a water molecule.

$P h C O C l + H_{2} O \to P h C O O H + H C l$

More positive carbon will be more reactive for the attack. Presence of $- N O_{2}$ which has $- M$ effect makes the $C$ of $p - N O_{2} C_{6} H_{4} C O C l$ more positive and most reactive. $O C H_{3}$ with $+ M$ effect makes the $C$ less positive and less reactive.

Therefore the order of reactivity is $p - O_{2} N C_{6} H_{4} C O C l > P h C O C l > p - C H_{3} O C_{6} H_{4} C O C l$

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