Question

The correct sequence of reactions to be performed to convert benzene into m-bromoaniline is :

• A. bromination, nitration, reduction
• B. reduction, nitration, bromination
• C. nitration, reduction, bromination
• D. nitration, bromination, reduction

Answer 1

The correct option is D nitration, bromination, reduction

As bromo group need to be directed at meta position first step is the nitration of benzene as nitro group is meta directing group. Then bromination will place bromo group in meta position and then reduction of nitro group to make the final product meta bromoaniline.