Question

The correct sequence of the oxidation state of underlined elements is:
$Na\underset{–}{B}{H}_4,N{a}_2\underset{–}{P_2}{O}_7,\underset{–}{N_3}H$

• A. $+3,+5,-\frac{1}{3}$
• B. $+5,+5,+\frac{1}{3}$
• C. $+3,+5,-1$
• D. $+5,+3,+\frac{1}{3}$

Answer 1

The correct option is A $+3,+5,-\frac{1}{3}$

$Na\underset{–}{B}{H}_4:+1+x+4(-1)=0\Rightarrow x=+3$

$N{a}_2\underset{–}{P_2}{O}_7:+4+2x+(-14)=0\Rightarrow x=+5$

$N_{3}H:3x+1=0\Rightarrow x=-\frac{1}{3}$