The correct set of four quantum numbers for the valence electron of cesium z -55 is-A- n -5- I -0- m 1-1- m s -1-2B- n -6- I -0- m 1-1- m s -1-8C- n -6- I -0- m 1-0- m s -1-2D- n -6- I -0- m 1-1- m s -1-2

The correct option is C n=6, I=0, m_1=0, m_s=+1/2_55Cs=[Xe]6s^1 So n=6, l=0, m_s=+1/2 ,m_1=0 ...

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Electric Field inside a Conductor under Electrodynamic Conditions

The correct s...

Question

The correct set of four quantum numbers for the valence electron of cesium (z = 55) is:

n = 6, I = 0, m_{1} = 0, m_{s} = + \frac{1}{2}

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n = 5, I = 0, m_{1} = - 1, m_{s} = - \frac{1}{2}

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n = 6, I = 0, m_{1} = + 1, m_{s} = - \frac{1}{2}

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n = 6, I = 0, m_{1} = + 1, m_{s} = + \frac{1}{2}

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Similar questions

n = 0

l = 0

m_{1} = 0

m_{s} = + 1 / 2

n = 1

l = 0

m_{1} = 0

m_{s} = - 1 / 2

n = 1

l = 1

m_{1} = 0

m_{s} = + 1 / 2

n = 2

l = 1

m_{1} = 0

m_{s} = - 1 / 2

n = 2

l = 3

m_{1} = - 3

m_{s} = + 1 / 2

n = 3

l = 1

m_{1} = 0

m_{s} = + 1 / 2

n = 4, l = 2, m_{1} = - 2, m_{s} = - 1 / 2

n = 3, l = 2, m_{1} = 1, m_{s} = + 1 / 2

n = 4, l = 1, m_{1} = 0, m_{s} = + 1 / 2

n = 3, l = 2, m_{1} = - 2, m_{s} = - 1 / 2

n = 3, l = 1, m_{1} = - 1, m_{s} = + 1 / 2

n = 4, l = 1, m_{1} = 0, m_{s} = + 1 / 2

Question 18

Out of the following pairs of electrons, identify the pairs of electrons present in degenerate orbitals.

(a) (i) $n = 3, l = 2, m_{l} = - 2, m_{s} = - \frac{1}{2}$ (ii) $n = 3, l = 2, m_{l} = - 1, m_{s} = - \frac{1}{2}$

(b) (i) $n = 3, l = 1, m_{l} = 1, m_{s} = + \frac{1}{2}$ (ii) $n = 3, l = 2, m_{l} = - 1, m_{s} = + \frac{1}{2}$

(d) (i) $n = 3, l = 2, m_{l} = + 2, m_{s} = - \frac{1}{2}$ (ii) $n = 3, l = 2, m_{l} = + 2, m_{s} = + \frac{1}{2}$

n = 4, l = 2, m_{l} = - 2, m_{s} = - 1 / 2

n = 3, l = 2, m_{l} = 1, m_{s} = + 1 / 2

n = 4, l = 1, m_{l} = 0, m_{s} = + 1 / 2

n = 3, l = 1, m_{l} = 1, m_{s} = - 1 / 2

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