Question

The correct set of four quantum numbers for the valence electrons of rubidium atom $[Z=37]$ is:

• A. $5,1,1,+\frac{1}{2}$
• B. $5,0,1,+\frac{1}{2}$
• C. $5,0,0,+\frac{1}{2}$
• D. $5,1,0,+\frac{1}{2}$

Answer 1

The correct option is C $5,0,0,+\frac{1}{2}$

The electronic configuration of rubidium (Z=37) is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{10}4s^{2}4p^{6}5s^1$.

The valence electron is present in $5s^1$ subshell.

Hence, the set of quantum numbers are $n=5,l=0,m=0$ and $s=+\frac{1}{2}$.

Hence, the correct option is $C$