The correct set of quantum numbers for the unpaired electron of chlorine atom (Z=17) is:

n=2,l=1,m=0

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n=2,l=1,m=1

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n=3,l=1,m=1

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n=3,l=0,m=0

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Solution

The correct option is C n=3,l=1,m=1
atomic number of Cl=17 , electronic configuration = $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{5}$ For 3p orbital n=3, l=1 m=-1,0,+1

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e^{-}

n l m

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n = 1, l = 0, m = 0

n = 2, l = 0, m = 0

n = 2, l = 1, m = 1

n = 3, l = 2, m = 1

n = 3, l = 2, m = 0

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