Question

The correct set of quantum numbers ($nlm$) for the unpaired $e^{-}$ of chlorine is:

• A. $210$
• B. $211$
• C. $311$
• D. $300$

Answer 1

The correct option is C $311$

The electronic configuration for $C{l}_{17}=\left[Ne\right]3s^{2}3p^5$.
Since the unpaired $e^{-}$ is in the $3p$ orbital, we have $n=3,l=1,m=1,0,-1$
The possible combinations are as follows:
($31-1$)
($310$)
($311$)