The correct stability order for oxides of elements of group $- 17$ is:

C l > B r > I

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C l > I > B r

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I > C l > B r

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I > B r > C l

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Solution

The correct option is D $I > C l > B r$
iodine oxygen bond is stable due to the greater polarity of bond and stability of chlorine oxygen bond is due to multiple bond formation with Orbital of chlorine atom now, be lier in better I and Cl, so it lacks both characteristics so, the stability order of oxide is given as
$I > C l > B r$

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Q. The correct order of polarizability is

I^{-}, B r^{-}, C l^{-}, F^{-}

Q. For the species

(I^{-}, C l^{-}, B r^{-})

, the increasing order of nucleophilicity in water would be:

For the following

(a) $I^{-}$ (b) $C l^{-}$ (c) $B r^{-}$
The increasing order of nucleophilicity would be

The correct order of the oxidizing power of Cl₂, Br₂, I₂ and O₂ is:

Among halogens, the correct order of amount of energy released in electron gain (electron gain enthalpy ) is
(a) F > Cl > Br > I (b) F < Cl < Br < I (c) F < Cl > Br > I (d) F < Cl < Br < I

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The correct stability order for oxides of elements of group −17 is:

The correct stability order for oxides of elements of group $- 17$ is: