The correct option is
B It can be zero for 3p orbital
Probability density is the square of wave function and hence is always positive . So, option d is wrong.
Probality density changes with distance (radius) from nucleus. It becomes zero at radial nodes.
In 1s graph, the probability density curve does not become zero at any distance hence, option (c) is wrong.
In 2s graph, the probability density curve becomes zero at a point which is know as node. Hence, potion (a) is wrong.
In 3p graph, we have a minimum curve which denotes the node where probability density is zero.
Hence, option (b) is the correct statement.