Question

The correct statements among (a) to (d) are :
(a) saline hydrides produce $H_2$ gas when reacted with $H_{2}O$.
(b) reaction of $LiAl{H}_4$ with $B{F}_3$ leads to $B_2{H}_6$.
(c) $P{H}_3$ and $C{H}_4$ are electron-rich and electron-precise hydrides, respectively.
(d) $HF$ and $C{H}_4$ are called as molecular hydride

• A. (a), (b), (c) and (d)
• B. (a), (c) and (d) only
• C. (c) and (d) only
• D. (a), (b) and (c) only

Answer 1

The correct option is A (a), (b), (c) and (d)

(a)
$\underset{\text{Saline/ionic hydride}}{MH}+H_{2}O\to MOH+H_2$

(b)
$4B{F}_3+3LiAl{H}_4\to 2B_2{H}_6+3LiF+3Al{F}_3$

(c)

Thus, $P{H}_3$ and $C{H}_4$ are electron-rich and electron-precise hydrides, respectively.

(d) $HF$ and $C{H}_4$ are molecular hydride because they are covalent molecules.

Hence, option (a) is the correct answer.