The correct structure of $F e (C O)_{5}$ is :

trigonal bipyramidal

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octahedral

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tetrahedral

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square pyramidal

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Solution

The correct option is A trigonal bipyramidal
$_{26} F e = 1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{2} 3 p^{6}, 4 s^{2} 4 p^{0}$

In $F e (C O)_{5},$ the F atom is in $d s p^{3}$ hybridised state. Therefore, the shape of molecule is trigonal bipyramidal. The hybridisation is as :

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