The correct structure of $F e {(C O)}_{5}$ is:

trigonal bipyramidal

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octahedral

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tetrahedral

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square pyramidal

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Solution

The correct option is A trigonal bipyramidal
$_{26} F e = 1 s^{2}, 2 s^{2} 2 p^{6}, 3 s^{2} 3 p^{6} 3 d^{6}, 4 s^{2} 4 p^{0}$

In $F e {(C O)}_{5}$ , the $F e$ atom is in $d s p^{3}$ hybridised state. Therefore, the shape of molecule is trigonal bipyramidal. The hybridisation is as:

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F e (C O)_{5}

What is the shape of $F e (C O)_{5}$ molecule and which of the following d - orbitals involved in hybridization?

{X Y}_{3}

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