Question

The correct truth table for the following logic circuit is:

• A. $\begin{array}{ccc}A& B& Y\\ 0& 0& 0\\ 0& 1& 1\\ 1& 0& 0\\ 1& 1& 1\end{array}$
• B. $\begin{array}{ccc}A& B& Y\\ 0& 0& 0\\ 0& 1& 1\\ 1& 0& 1\\ 1& 1& 0\end{array}$
• C.
  $\begin{array}{ccc}A& B& Y\\ 0& 0& 1\\ 0& 1& 0\\ 1& 0& 1\\ 1& 1& 0\end{array}$
• D. $\begin{array}{ccc}A& B& Y\\ 0& 0& 1\\ 0& 1& 0\\ 1& 0& 0\\ 1& 1& 1\end{array}$

Answer 1

The correct option is D $\begin{array}{ccc}A& B& Y\\ 0& 0& 1\\ 0& 1& 0\\ 1& 0& 0\\ 1& 1& 1\end{array}$


If $A=B=0$, then output $y=1$
If $A=B=1$, then output $y=1$