The correct value for the relative lowering of vapour pressure of a very dilute solution is equal to:

mole fraction of solute

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mole fraction of solvent

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ratio of moles of solute to moles of solvent

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ratio of moles of solvent to moles of solute

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Solution

The correct options are
B ratio of moles of solute to moles of solvent
C mole fraction of solute
we have, $\frac{P_{B}^{0} - P_{t}}{P_{B}^{0}} = x_{A}$
or we have
$\frac{P_{B}^{0} - P_{t}}{P_{B}^{0}} = x_{A}$ = $\frac{n_{A}}{n_{A} + n_{B}}$
the value of $n_{A}$ is very samall for dilute solution, so we have;

$\frac{P_{B}^{0} - P_{t}}{P_{B}^{0}} = x_{A}$ = $\frac{n_{A}}{n_{B}}$

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Similar questions

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The correct value for the relative lowering of vapour pressure of a very dilute solution is equal to:

The correct options are B ratio of moles of solute to moles of solvent C mole fraction of solutewe have, P0B−PtP0B=xAor we have P0B−PtP0B=xA = nAnA+nB the value of nA is very samall for dilute solution, so we have;P0B−PtP0B=xA = nAnB