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Standard X

Chemistry

Volume of Gases and Number of Moles

The correct v...

Question

The correct value of Avogadro’s number is :

6.021× 10²¹

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6.023× 10²³

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6.021

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0.0621

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Solution

The correct option is B
6.023× 10²³

Avogadro's number is defined as the number of elementary particles (molecules, atoms, compounds, etc.) per mole of a substance. It is equal to $6.023 \times 10^{23}$ mol ^-¹ and is expressed as the symbol N _A.

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Similar questions

Q. Since Avogadro number is

6.023 \times 10^{23}

and atomic mass of nitrogen is

14

amu, one mole of

N_{2}

gas will have:

If the value of Avogadro number is 6.023 $\times 10^{23} m o l^{- 1}$ and the value of Boltzmann constant is 1.380 $\times 10^{- 23} J K^{- 1},$ then the number of significant digits in the calculated value of the universal gas constant is ___

Q. What is the distance between

{N a}^{+}

and

{C l}^{-}

ions in

N a C l

crystal if its density is

2.165 g {c m}^{- 3}

.[Atomic mass of

N a - 23 u, C l = 35.5 u

, Avogadro,s Number=

6.023 \times 10^{23}

]

Q. The number of chlorine atoms in 20 mL of chlorine gas at STP is

x \times 10^{21}

. The value of x (Rounded off to the Nearest integer) is
.
[Assume chlorine is an ideal gas at STP,

N_{A} = 6.023 \times 10^{23}

]

Q. The number of chlorine atoms in 20 mL of chlorine gas at STP is

10^{21}

. (Round off to the Nearest Integer).

[A s s u m e c h l o r i n e i s a n i d e a l g a s a t S T P R = 0.083 L b a r m o l^{- 1} K^{- 1}, N_{A} = 6.023 \times 10^{23}]

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The correct value of Avogadro’s number is :

The correct option is B 6.023× 1023 Avogadro's number is defined as the number of elementary particles (molecules, atoms, compounds, etc.) per mole of a substance. It is equal to 6.023×1023 mol -1 and is expressed as the symbol N A.

The correct option is B
6.023× 10²³

Avogadro's number is defined as the number of elementary particles (molecules, atoms, compounds, etc.) per mole of a substance. It is equal to $6.023 \times 10^{23}$ mol ^-¹ and is expressed as the symbol N _A.