Question

The correct value of the gas constant $\mathrm{R}$ is close to

• A. $0.082\mathrm{L}-\mathrm{atmK}$
• B. $0.082\mathrm{L}-{\mathrm{atmK}}^{-1}{\mathrm{mol}}^{-1}$
• C. $0.082\mathrm{L}-{\mathrm{atm}}^{-1}\mathrm{K}{\mathrm{mol}}^{-1}$

Answer 1

The correct option is B

$0.082\mathrm{L}-{\mathrm{atmK}}^{-1}{\mathrm{mol}}^{-1}$

The explanation for the correct option:

Option (b) $0.082\mathrm{L}\mathrm{atm}{\mathrm{K}}^{-1}{\mathrm{mol}}^{-1}$

Gas constant:

• The gas constant ($\mathrm{R}$) is defined as the product of pressure and volume.
• It is measured in terms of energy per temperature rise per mole. $\mathrm{R}$ in atm has a constant value.
• However, the value of the gas constant can be stated in a variety of units.
• $\mathrm{R}$ is also known as the ideal gas constant, the universal gas constant, and the molar constant.
• The value of $\mathrm{R}$ at atm that is at standard atmospheric pressure is

$\mathrm{R}=8.3144598\mathrm{J}{\mathrm{mol}}^{-1}{\mathrm{K}}^{-1}$

• When pressure is expressed in the atmosphere and volume in litres, then the value of $\mathrm{R}$ at STP for one mole of gas is

$\mathrm{R}=\frac{1\mathrm{atm}\times 22.414\mathrm{L}}{1\mathrm{mole}\times 273.15\mathrm{K}}=0.082\mathrm{L}\mathrm{atm}{\mathrm{K}}^{-1}{\mathrm{mol}}^{-1}$

Hence, the correct option is (b) $0.082\mathrm{L}\mathrm{atm}{\mathrm{K}}^{-1}{\mathrm{mol}}^{-1}$.