The corresponding altitudes of two similar triangles are $6 c m$ and $9 c m$ respectively. Find the ratio of their areas.

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Solution

For similar triangles, ratio of areas of the triangles is equal to squares of the ratio of corresponding sides.
Ratio of area of triangles $= (\frac{6}{9})^{2}$
Ratio of area of triangles $= (\frac{2}{3})^{2}$
Ratio of area of triangles $= \frac{4}{9}$

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The corresponding altitudes of two similar triangles are 6cm and 9cm respectively. Find the ratio of their areas.

For similar triangles, ratio of areas of the triangles is equal to squares of the ratio of corresponding sides.Ratio of area of triangles =(69)2Ratio of area of triangles =(23)2Ratio of area of triangles =49

The corresponding altitudes of two similar triangles are $6 c m$ and $9 c m$ respectively. Find the ratio of their areas.

For similar triangles, ratio of areas of the triangles is equal to squares of the ratio of corresponding sides.
Ratio of area of triangles $= (\frac{6}{9})^{2}$
Ratio of area of triangles $= (\frac{2}{3})^{2}$
Ratio of area of triangles $= \frac{4}{9}$