The corresponding sides of 2 similar triangles $△ A B C$ and $△ P Q R$ are in the ratio 5 : 2. The length of side PR (in cm) is___________.
Given that AB = 3 cm and AC = 10 cm.

5 cm

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6 cm

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4 cm

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3 cm

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Solution

The correct option is C
4 cm

$△ A B C$ and $△ P Q R$ are similar.

So,
$\frac{A C}{P R}$ is equal to the ratio of corresponding sides.

$\frac{A C}{P R} = \frac{5}{2}$ .

Therefore,
$P R = (\frac{2}{5})$ AC = $\frac{2}{5} \times 10$

$P R = 4 c m$ .

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Similar questions

The corresponding sides of 2 similar triangles $△ A B C$ and $△ P Q R$ are in the ratio 5 : 2. The length of side PR (in cm) is___________.
Given that AB = 3 cm and AC = 10 cm.

The corresponding sides of 2 similar triangles $△ A B C$ and $△ P Q R$ are in the ratio 5:2. Given that AB=3 cm and AC=10 cm,the length of side PR (in cm) is___________.

$△ A B C$ is similar to $△ P Q R$ , in $△ A B C, A B = 3.6 c m, B C = 4 c m$ and $A C = 4.2 c m$ . The corresponding sides of $△ A B C$ and $△ P Q R$ are in the ratio $2 : 3$ . Construct $△ P Q R$ .

Find $m ∠ P R Q$ (in deg.)

Q. In triangle ABC, AB = 2.2 cm, BC = 1.5 cm and AC = 2.3 cm. In triangle XYZ, XY = 4.4 cm, YZ = 3 cm and XZ = 4.6 cm. Find the ratio AB : XY, BC : YZ, AC : XZ. Are the lengths of corresponding sides of

△

ABC and

△

XYZ are in proportion?

Q. Draw a

△ A B C

in which

B C = 6 c m, A B = 4 c m

and

A C = 5 c m

. Draw a triangle similar to

△ A B C

with its sides equal to

(\frac{3}{4})^{t h}

of the corresponding sides of

△ A B C

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The corresponding sides of 2 similar triangles △ABC and △PQR are in the ratio 5 : 2. The length of side PR (in cm) is___________. Given that AB = 3 cm and AC = 10 cm.

The correct option is C 4 cm △ABC and △PQR are similar. So, ACPR is equal to the ratio of corresponding sides. ACPR=52. Therefore, PR=(25) AC = 25×10 PR=4 cm.

The corresponding sides of 2 similar triangles $△ A B C$ and $△ P Q R$ are in the ratio 5 : 2. The length of side PR (in cm) is___________.
Given that AB = 3 cm and AC = 10 cm.

The correct option is C
4 cm

$△ A B C$ and $△ P Q R$ are similar.

So,
$\frac{A C}{P R}$ is equal to the ratio of corresponding sides.

$\frac{A C}{P R} = \frac{5}{2}$ .

Therefore,
$P R = (\frac{2}{5})$ AC = $\frac{2}{5} \times 10$

$P R = 4 c m$ .