The corresponding sides of two similar triangles ABC and DEF are BC = 9.1 cm and EF = 6.5 cm. If the perimeter of $Δ D E F$ is 25 cm, find the perimeter of $Δ A B C$ .

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Solution

$∵ Δ A B C \sim Δ D E F$

$\frac{P e r i m e t e r o f Δ D E F}{P e r i m e t e r o f Δ A B C} = \frac{D E}{A B}$

$\frac{25}{P e r i m e t e r o f Δ A B C} = \frac{6.5}{9.1}$

$P e r i m e t e r o f Δ A B C = \frac{9.1}{6.5} \times 25 = 35 c m$

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Q. ∆ABC ∼ ∆DEF such that AB = 9.1 cm and DE = 6.5 cm. If the perimeter of ∆DEF is 25 cm, what is the perimeter of ∆ABC?
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Triangle $A B C$ is such that $A B = 3 c m, B C = 2 c m$ and $C A = 2.5 c m$ . Triangle $D E F$ is similar to $△ A B C$ . If $E F = 4 c m$ , then the perimeter of $△ D E F$ is:

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ABC is such that AB = 3 cm, BC = 2 cm and CA = 2.5 cm.

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The corresponding sides of two similar triangles ABC and DEF are BC = 9.1 cm and EF = 6.5 cm. If the perimeter of ΔDEF is 25 cm, find the perimeter of ΔABC.

∵ΔABC∼ΔDEF Perimeter of ΔDEFPerimeter of ΔABC=DEAB 25Perimeter of ΔABC=6.59.1 Perimeter of ΔABC=9.16.5×25=35 cm

The corresponding sides of two similar triangles ABC and DEF are BC = 9.1 cm and EF = 6.5 cm. If the perimeter of $Δ D E F$ is 25 cm, find the perimeter of $Δ A B C$ .

$∵ Δ A B C \sim Δ D E F$

$\frac{P e r i m e t e r o f Δ D E F}{P e r i m e t e r o f Δ A B C} = \frac{D E}{A B}$

$\frac{25}{P e r i m e t e r o f Δ A B C} = \frac{6.5}{9.1}$

$P e r i m e t e r o f Δ A B C = \frac{9.1}{6.5} \times 25 = 35 c m$