The cosine of the angle between the tangents from the origin to the circle $x^{2} + y^{2} - 14 x + 2 y + 25$ = 0 is

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Solution

The correct option is C
0

r = 5
$\sqrt{s_{11}} = 5 t a n \frac{θ}{2} = \frac{r}{\sqrt{s_{11}}} = 1. θ = 90^{\circ} c o s θ = 0$

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The cosine of the angle between the tangents from the origin to the circle x2+y2−14x+2y+25 = 0 is

The correct option is C 0 r = 5 √s11=5tanθ2=r√s11=1.θ=90∘cos θ=0

The cosine of the angle between the tangents from the origin to the circle $x^{2} + y^{2} - 14 x + 2 y + 25$ = 0 is

The correct option is C
0

r = 5
$\sqrt{s_{11}} = 5 t a n \frac{θ}{2} = \frac{r}{\sqrt{s_{11}}} = 1. θ = 90^{\circ} c o s θ = 0$