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Byju's Answer
Standard X
Mathematics
Elimination Method of Finding Solution of a Pair of Linear Equations
The cost of ...
Question
The cost of
1
pencil and
3
erasers is Rs.
10
and the cost of
4
pencils and
6
erasers is
R
s
.28
.Find the cost of
5
pencils and
4
erasers.
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Solution
Let
x
and
y
be the cost of
1
pencil and
1
eraser respectively.
According to the question-
x
+
3
y
=
10
.
.
.
.
.
(
1
)
4
x
+
6
y
=
28
⇒
2
x
+
3
y
=
14
.
.
.
.
.
(
2
)
Subtracting equation
(
1
)
from
(
2
)
, e have
(
2
x
+
3
y
)
−
(
x
+
3
y
)
=
14
−
10
2
x
+
3
y
−
x
−
3
y
=
4
x
=
4
Subsituting the value of
x
in equation
(
1
)
, we have
4
+
3
y
=
10
⇒
3
y
=
6
⇒
y
=
6
3
=
2
Hence the cost of
1
pencil and
1
eraser respectively is
R
s
.
4
and
R
s
.
2
respectively.
Now,
Cost of
5
pencils and
4
erasers
=
5
x
+
4
y
=
(
5
×
4
)
+
(
4
×
2
)
=
20
+
8
=
28
Hence the cost of
5
pencils and
4
erasers is
R
s
.
28
.
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