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Byju's Answer
Standard IX
Mathematics
Solution of Linear Equation in 2 Variables
The cost of ...
Question
The cost of
11
pencils and
3
erasers is Rs.
50
and the cost of
8
pencils and
3
erasers is Rs.
38
. Find the cost of each pencil and each eraser.
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Solution
Let x denote the cost of a pencil in rupees and y denote the cost of an eraser in rupees. Then according to the given information we have
11
x
+
3
y
=
50
(1)
8
x
+
3
y
=
38
(2)
Subtracting (2) from (1) we get, x 3 = 12 which gives 4 = x .
Now substitute x = 4 in (1) to find the value of y. We get,
11
(
4
)
+
3
y
=
50
i.e., y=2
Therefore,x=4 and y = 2 is the solution of the given pair of equations.
Thus, the cost of a pencil is Rs. 4 and that of an eraser is Rs. 2.
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