Question

The cost of $2$ kg of Apples and $1$ kg grapes on a day was bound to be Rs. $160$. After a moth the lost of $4$ kg grapes and $2$ kg graps is Rs. $300$. Represent this situation algebraicallyand geometrically.

Answer 1

Let us consider that price of apple be $x$ & grapes be $y$

Case $1:$

$2x+y=160$ $..............\left(1\right)$

Case $2:$

$4x+2y=300$

$2x+y=150$ $..........\left(2\right)$

Now,

Put simultaneously $x$ and $y$ values

in eq $\left(1\right)$ in eq $\left(2\right)$

$2x+y=160$ $2x+y=150$

$x=50$ $x=50$

$100+y=160$ $100+y=150$

$y=60$ $y=50$

$x=30$ $x=30$

$60+y=160$ $60+y=150$

$y=100$ $y=90$

Then, mark this point on graph and you will find that both the lines will be parallel to each other.

Hence, this is the answer.