The cost of 2 kg of apples and 1 kg of grapes on a day was found to be Rs 160. After a month, the cost of 4 kg of apples and 2 kg of grapes is Rs 300. Represent the situation algebraically and geometrically.

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Solution

Let the cost of 1 kg of apples be Rs x.

And, cost of 1 kg of grapes = Rs y

According to the question, the algebraic representation is

For ,

The solution table is

x

50

60

70

y

60

40

20

For 4x + 2y = 300,

The solution table is

x

70

80

75

y

10

−10

0

The graphical representation is as follows.

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Question 3
The cost of 2 kg of apples and 1kg of grapes on a day was found to be Rs 160. After a month, the cost of 4 kg of apples and 2 kg of grapes is Rs 300. Represent the situation algebraically and geometrically.

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The cost of $2 k g$ of apples and $1 k g$ of grapes on a day was found to be $R s . 160$ . The cost of $4 k g$ of apples and $3 k g$ of grapes is $R s . 360$ . Find the cost of per kg apples and grapes.

Q. The cost of

2

kg of apples and

1

kg of grapes on a day was found to be Rs.

160

. After a month, the cost of

4

kg of apples and

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kg of grapes is Rs.

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. Represent, the situation algebraically and graphically.

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The cost of 2 kg of apples and 1 kg of grapes on a day was found to be Rs 160. After a month, the cost of 4 kg of apples and 2 kg of grapes is Rs 300. Represent the situation algebraically and geometrically.

Let the cost of 1 kg of apples be Rs x. And, cost of 1 kg of grapes = Rs y According to the question, the algebraic representation is For , The solution table is x 50 60 70 y 60 40 20 For 4x + 2y = 300, The solution table is x 70 80 75 y 10 −10 0 The graphical representation is as follows.