The cost of $2$ kg of apples and $1$ kg of grapes on a day was found to be Rs. $160$ . After a month, the cost of $4$ kg of apples and $2$ kg of grapes is Rs. $300$ . Represent, the situation algebraically and graphically.

2 x + y = 160

4 x + 2 y = 300

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x + 2 y = 160

4 x + 2 y = 300

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x + 2 y = 160

2 x - 4 y = 300

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None of these

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Solution

The correct option is A $2 x + y = 160$
$4 x + 2 y = 300$

The graphs show Rs.10 increment in the gross price.
$x$ $y = 160 - 2 x$ $y = 150 - 2 x$
-50 260 250
0 160 1 50
50 60 50
100 -40 -50
Let the cost of $1$ kg of apple $= x$ and that of $1$ kg of grapes $= y$ , when $x$ & $y$ are in Rs.
So, by the first condition,

$2 x + y = 160$ ....(i) and
by the second condition, we have
$4 x + 2 y = 300$ ....(ii)

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