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Standard IX

Mathematics

Lines Parallel to Coordinate Axes

The cost of ...

Question

The cost of $2$ kg of apples and $1$ kg of grapes on the day was found to be Rs. $160$ . After a month the cost of $4$ kg of apples $2$ kg of grapes is Rs. $300$ . Represent the situation algebraically.

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Solution

Let cost of apple/kg = x

cost of graps / kg=y

then from given conditions
2x+y=600

4x+2y=300

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The cost of 2kg of apples and 1kg of grapes on the day was found to be Rs.160. After a month the cost of 4kg of apples 2kg of grapes is Rs.300. Represent the situation algebraically.

Let cost of apple/kg = x cost of graps / kg=y then from given conditions 2x+y=600 4x+2y=300

The cost of $2$ kg of apples and $1$ kg of grapes on the day was found to be Rs. $160$ . After a month the cost of $4$ kg of apples $2$ kg of grapes is Rs. $300$ . Represent the situation algebraically.

Let cost of apple/kg = x

cost of graps / kg=y

then from given conditions
2x+y=600

4x+2y=300